5x(3-4x)+x(11x-2)=6x(1-x)-3(2+x^2)

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Solution for 5x(3-4x)+x(11x-2)=6x(1-x)-3(2+x^2) equation: 



5x(3-4x)+x(11x-2)=6x(1-x)-3(2+x^2)

We move all terms to the left:

5x(3-4x)+x(11x-2)-(6x(1-x)-3(2+x^2))=0

We add all the numbers together, and all the variables

-(6x(-1x+1)-3(2+x^2))+5x(-4x+3)+x(11x-2)=0

We multiply parentheses

-(6x(-1x+1)-3(2+x^2))-20x^2+11x^2+15x-2x=0



We calculate terms in parentheses: -(6x(-1x+1)-3(2+x^2)), so:

6x(-1x+1)-3(2+x^2)

determiningTheFunctionDomain
-3(2+x^2)+6x(-1x+1)

We multiply parentheses

-3x^2-6x^2+6x-6

We add all the numbers together, and all the variables

-9x^2+6x-6

Back to the equation:

-(-9x^2+6x-6)



We add all the numbers together, and all the variables

-9x^2-(-9x^2+6x-6)+13x=0

We get rid of parentheses

-9x^2+9x^2-6x+13x+6=0

We add all the numbers together, and all the variables

7x+6=0

We move all terms containing x to the left, all other terms to the right

7x=-6

x=-6/7

x=-6/7

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